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100210212201103 is a prime number
BaseRepresentation
bin10110110010010000000010…
…000110011110001010001111
3111010211000001222122210002121
4112302100002012132022033
5101113321003310413403
6553043534055433411
730051643322313304
oct2662200206361217
9433730058583077
10100210212201103
1129a25a043491a4
12b2a54b1385867
1343bba230bc264
141aa62b32d30ab
15b8ba6e56b3bd
hex5b240219e28f

100210212201103 has 2 divisors, whose sum is σ = 100210212201104. Its totient is φ = 100210212201102.

The previous prime is 100210212201097. The next prime is 100210212201193. The reversal of 100210212201103 is 301102212012001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100210212201103 - 237 = 100072773247631 is a prime.

It is a super-2 number, since 2×1002102122011032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100210212201193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50105106100551 + 50105106100552.

It is an arithmetic number, because the mean of its divisors is an integer number (50105106100552).

Almost surely, 2100210212201103 is an apocalyptic number.

100210212201103 is a deficient number, since it is larger than the sum of its proper divisors (1).

100210212201103 is an equidigital number, since it uses as much as digits as its factorization.

100210212201103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100210212201103 its reverse (301102212012001), we get a palindrome (401312424213104).

The spelling of 100210212201103 in words is "one hundred trillion, two hundred ten billion, two hundred twelve million, two hundred one thousand, one hundred three".