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10021112121133 is a prime number
BaseRepresentation
bin1001000111010011100011…
…0101000000011100101101
31022111000020112102010110201
42101310320311000130231
52303141214200334013
633151345123033501
72053000333410001
oct221647065003455
938430215363421
1010021112121133
113213a255a7113
12115a1aa20b891
13578caa068ca9
1426904adca701
15125a1363b3dd
hex91d38d4072d

10021112121133 has 2 divisors, whose sum is σ = 10021112121134. Its totient is φ = 10021112121132.

The previous prime is 10021112121109. The next prime is 10021112121151. The reversal of 10021112121133 is 33112121112001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8801914107204 + 1219198013929 = 2966802^2 + 1104173^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10021112121133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10021112121133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10021112121733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010556060566 + 5010556060567.

It is an arithmetic number, because the mean of its divisors is an integer number (5010556060567).

Almost surely, 210021112121133 is an apocalyptic number.

It is an amenable number.

10021112121133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10021112121133 is an equidigital number, since it uses as much as digits as its factorization.

10021112121133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 10021112121133 its reverse (33112121112001), we get a palindrome (43133233233134).

The spelling of 10021112121133 in words is "ten trillion, twenty-one billion, one hundred twelve million, one hundred twenty-one thousand, one hundred thirty-three".