Base | Representation |
---|---|
bin | 101110101010100001… |
… | …1011011110000110000 |
3 | 100120122220001222200220 |
4 | 1131111003123300300 |
5 | 3120213032230222 |
6 | 114011510013040 |
7 | 10145220145632 |
oct | 1352503336060 |
9 | 316586058626 |
10 | 100211211312 |
11 | 39554686303 |
12 | 17508647180 |
13 | 95b04c0a54 |
14 | 4bc9120a52 |
15 | 2917a5ab5c |
hex | 17550dbc30 |
100211211312 has 80 divisors (see below), whose sum is σ = 276265746432. Its totient is φ = 31191229440.
The previous prime is 100211211283. The next prime is 100211211407. The reversal of 100211211312 is 213112112001.
It is a super-3 number, since 3×1002112113123 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 100211211291 and 100211211300.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 379864 + ... + 587127.
Almost surely, 2100211211312 is an apocalyptic number.
100211211312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
100211211312 is an abundant number, since it is smaller than the sum of its proper divisors (176054535120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100211211312 is a wasteful number, since it uses less digits than its factorization.
100211211312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 967146 (or 967140 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 100211211312 its reverse (213112112001), we get a palindrome (313323323313).
The spelling of 100211211312 in words is "one hundred billion, two hundred eleven million, two hundred eleven thousand, three hundred twelve".
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