Base | Representation |
---|---|
bin | 10010101010100111… |
… | …11000111111110111 |
3 | 221212101200022201121 |
4 | 21111103320333313 |
5 | 131010412242101 |
6 | 4334221204411 |
7 | 503222616646 |
oct | 112523707767 |
9 | 27771608647 |
10 | 10021212151 |
11 | 4282793015 |
12 | 1b38100707 |
13 | c39206542 |
14 | 6b0cc535d |
15 | 3d9b9d0a1 |
hex | 2554f8ff7 |
10021212151 has 2 divisors, whose sum is σ = 10021212152. Its totient is φ = 10021212150.
The previous prime is 10021212119. The next prime is 10021212181. The reversal of 10021212151 is 15121212001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10021212151 - 25 = 10021212119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10021212101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010606075 + 5010606076.
It is an arithmetic number, because the mean of its divisors is an integer number (5010606076).
Almost surely, 210021212151 is an apocalyptic number.
10021212151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10021212151 is an equidigital number, since it uses as much as digits as its factorization.
10021212151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 10021212151 its reverse (15121212001), we get a palindrome (25142424152).
The spelling of 10021212151 in words is "ten billion, twenty-one million, two hundred twelve thousand, one hundred fifty-one".
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