10021320031 has 2 divisors, whose sum is σ = 10021320032. Its totient is φ = 10021320030.

The previous prime is 10021320013. The next prime is 10021320107. The reversal of 10021320031 is 13002312001.

Together with previous prime (10021320013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10021320031 - 2¹¹ = 10021317983 is a prime.

It is a super-2 number, since 2×10021320031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10021319993 and 10021320020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10021320131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010660015 + 5010660016.

It is an arithmetic number, because the mean of its divisors is an integer number (5010660016).

Almost surely, 2^10021320031 is an apocalyptic number.

10021320031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10021320031 is an equidigital number, since it uses as much as digits as its factorization.

10021320031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 10021320031 its reverse (13002312001), we get a palindrome (23023632032).

The spelling of 10021320031 in words is "ten billion, twenty-one million, three hundred twenty thousand, thirty-one".