Base | Representation |
---|---|
bin | 10010101010101000… |
… | …10111000001011011 |
3 | 221212101220120102102 |
4 | 21111110113001123 |
5 | 131010430211011 |
6 | 4334223554015 |
7 | 503223641333 |
oct | 112524270133 |
9 | 27771816372 |
10 | 10021335131 |
11 | 4282867455 |
12 | 1b3815b90b |
13 | c3924a502 |
14 | 6b0d180c3 |
15 | 3d9bc473b |
hex | 25551705b |
10021335131 has 2 divisors, whose sum is σ = 10021335132. Its totient is φ = 10021335130.
The previous prime is 10021335109. The next prime is 10021335133. The reversal of 10021335131 is 13153312001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10021335131 - 210 = 10021334107 is a prime.
It is a super-2 number, since 2×100213351312 (a number of 21 digits) contains 22 as substring.
Together with 10021335133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10021335133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010667565 + 5010667566.
It is an arithmetic number, because the mean of its divisors is an integer number (5010667566).
Almost surely, 210021335131 is an apocalyptic number.
10021335131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10021335131 is an equidigital number, since it uses as much as digits as its factorization.
10021335131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 10021335131 its reverse (13153312001), we get a palindrome (23174647132).
The spelling of 10021335131 in words is "ten billion, twenty-one million, three hundred thirty-five thousand, one hundred thirty-one".
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