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1002141300111 = 37377789165587
BaseRepresentation
bin11101001010101000100…
…01101011010110001111
310112210200221122202000120
432211110101223112033
5112404341133100421
62044213302000023
7132254665334340
oct16452421532617
93483627582016
101002141300111
11357007702406
1214227b116013
1373669ab6c23
143670a9a40c7
151b10473a8c6
hexe95446b58f

1002141300111 has 32 divisors (see below), whose sum is σ = 1568555512320. Its totient is φ = 557100187776.

The previous prime is 1002141300077. The next prime is 1002141300119. The reversal of 1002141300111 is 1110031412001.

It is not a de Polignac number, because 1002141300111 - 221 = 1002139202959 is a prime.

It is a super-2 number, since 2×10021413001112 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1002141300119) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5969260 + ... + 6134846.

It is an arithmetic number, because the mean of its divisors is an integer number (49017359760).

Almost surely, 21002141300111 is an apocalyptic number.

1002141300111 is a deficient number, since it is larger than the sum of its proper divisors (566414212209).

1002141300111 is a wasteful number, since it uses less digits than its factorization.

1002141300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173423.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1002141300111 its reverse (1110031412001), we get a palindrome (2112172712112).

The spelling of 1002141300111 in words is "one trillion, two billion, one hundred forty-one million, three hundred thousand, one hundred eleven".

Divisors: 1 3 7 21 37 111 259 777 7789 23367 54523 163569 165587 288193 496761 864579 1159109 2017351 3477327 6052053 6126719 18380157 42887033 128661099 1289757143 3869271429 9028300001 27084900003 47721014291 143163042873 334047100037 1002141300111