1002152250131 has 2 divisors, whose sum is σ = 1002152250132. Its totient is φ = 1002152250130.

The previous prime is 1002152250101. The next prime is 1002152250161. The reversal of 1002152250131 is 1310522512001.

It is a balanced prime because it is at equal distance from previous prime (1002152250101) and next prime (1002152250161).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1002152250131 is a prime.

It is a super-2 number, since 2×1002152250131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1002152250097 and 1002152250106.

It is not a weakly prime, because it can be changed into another prime (1002152250101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501076125065 + 501076125066.

It is an arithmetic number, because the mean of its divisors is an integer number (501076125066).

Almost surely, 2^{1002152250131} is an apocalyptic number.

1002152250131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002152250131 is an equidigital number, since it uses as much as digits as its factorization.

1002152250131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 1002152250131 its reverse (1310522512001), we get a palindrome (2312674762132).

The spelling of 1002152250131 in words is "one trillion, two billion, one hundred fifty-two million, two hundred fifty thousand, one hundred thirty-one".