Base | Representation |
---|---|
bin | 101110101010110010… |
… | …1000010110100000001 |
3 | 100120200111122121201022 |
4 | 1131111211002310001 |
5 | 3120222311201032 |
6 | 114012422515225 |
7 | 10145355063053 |
oct | 1352545026401 |
9 | 316614577638 |
10 | 100220022017 |
11 | 39559653985 |
12 | 1750b595b15 |
13 | 95b228719b |
14 | 4bca3758d3 |
15 | 29186eb512 |
hex | 1755942d01 |
100220022017 has 2 divisors, whose sum is σ = 100220022018. Its totient is φ = 100220022016.
The previous prime is 100220021977. The next prime is 100220022029. The reversal of 100220022017 is 710220022001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87942495601 + 12277526416 = 296551^2 + 110804^2 .
It is a cyclic number.
It is not a de Polignac number, because 100220022017 - 218 = 100219759873 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100220021986 and 100220022004.
It is not a weakly prime, because it can be changed into another prime (100220022037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50110011008 + 50110011009.
It is an arithmetic number, because the mean of its divisors is an integer number (50110011009).
Almost surely, 2100220022017 is an apocalyptic number.
It is an amenable number.
100220022017 is a deficient number, since it is larger than the sum of its proper divisors (1).
100220022017 is an equidigital number, since it uses as much as digits as its factorization.
100220022017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 100220022017 its reverse (710220022001), we get a palindrome (810440044018).
The spelling of 100220022017 in words is "one hundred billion, two hundred twenty million, twenty-two thousand, seventeen".
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