10022012113 has 2 divisors, whose sum is σ = 10022012114. Its totient is φ = 10022012112.

The previous prime is 10022012069. The next prime is 10022012129. The reversal of 10022012113 is 31121022001.

10022012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8885513169 + 1136498944 = 94263^2 + 33712^2 .

It is a cyclic number.

It is not a de Polignac number, because 10022012113 - 2¹⁷ = 10021881041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10022012093 and 10022012102.

It is not a weakly prime, because it can be changed into another prime (10022012153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011006056 + 5011006057.

It is an arithmetic number, because the mean of its divisors is an integer number (5011006057).

Almost surely, 2^10022012113 is an apocalyptic number.

It is an amenable number.

10022012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10022012113 is an equidigital number, since it uses as much as digits as its factorization.

10022012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Subtracting from 10022012113 its sum of digits (13), we obtain a square (10022012100 = 100110²).

Adding to 10022012113 its reverse (31121022001), we get a palindrome (41143034114).

The spelling of 10022012113 in words is "ten billion, twenty-two million, twelve thousand, one hundred thirteen".