Base | Representation |
---|---|
bin | 1001000111010111000011… |
… | …1010101001110100111111 |
3 | 1022111002200010002002201001 |
4 | 2101311300322221310333 |
5 | 2303200131100003224 |
6 | 33152022340031131 |
7 | 2053032550665535 |
oct | 221656072516477 |
9 | 38432603062631 |
10 | 10022053125439 |
11 | 3214368795623 |
12 | 115a4113924a7 |
13 | 5790c9cbb384 |
14 | 2690d9d7c155 |
15 | 125a6b067544 |
hex | 91d70ea9d3f |
10022053125439 has 2 divisors, whose sum is σ = 10022053125440. Its totient is φ = 10022053125438.
The previous prime is 10022053125281. The next prime is 10022053125463. The reversal of 10022053125439 is 93452135022001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10022053125439 - 219 = 10022052601151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10022053125398 and 10022053125407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10022053125479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011026562719 + 5011026562720.
It is an arithmetic number, because the mean of its divisors is an integer number (5011026562720).
Almost surely, 210022053125439 is an apocalyptic number.
10022053125439 is a deficient number, since it is larger than the sum of its proper divisors (1).
10022053125439 is an equidigital number, since it uses as much as digits as its factorization.
10022053125439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 10022053125439 in words is "ten trillion, twenty-two billion, fifty-three million, one hundred twenty-five thousand, four hundred thirty-nine".
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