Base | Representation |
---|---|
bin | 1001000111010111100110… |
… | …1011010111001110110011 |
3 | 1022111010001100122210102122 |
4 | 2101311321223113032303 |
5 | 2303200431212041201 |
6 | 33152045110304455 |
7 | 2053036314235121 |
oct | 221657153271663 |
9 | 38433040583378 |
10 | 10022200112051 |
11 | 3214433759866 |
12 | 115a45265812b |
13 | 5791215a37ba |
14 | 2691116c0911 |
15 | 125a78dede1b |
hex | 91d79ad73b3 |
10022200112051 has 2 divisors, whose sum is σ = 10022200112052. Its totient is φ = 10022200112050.
The previous prime is 10022200111943. The next prime is 10022200112053. The reversal of 10022200112051 is 15021100222001.
It is a strong prime.
It is an emirp because it is prime and its reverse (15021100222001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10022200112051 is a prime.
Together with 10022200112053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10022200112053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011100056025 + 5011100056026.
It is an arithmetic number, because the mean of its divisors is an integer number (5011100056026).
Almost surely, 210022200112051 is an apocalyptic number.
10022200112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10022200112051 is an equidigital number, since it uses as much as digits as its factorization.
10022200112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 10022200112051 its reverse (15021100222001), we get a palindrome (25043300334052).
The spelling of 10022200112051 in words is "ten trillion, twenty-two billion, two hundred million, one hundred twelve thousand, fifty-one".
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