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1002234404113 is a prime number
BaseRepresentation
bin11101001010110011101…
…00110101110100010001
310112210221102211220200221
432211121310311310101
5112410034001412423
62044230425313041
7132260205605515
oct16453164656421
93483842756627
101002234404113
11357055213868
121422a6335781
1373683184957
14367190bc145
151b10c9cbe5d
hexe959d35d11

1002234404113 has 2 divisors, whose sum is σ = 1002234404114. Its totient is φ = 1002234404112.

The previous prime is 1002234404107. The next prime is 1002234404137. The reversal of 1002234404113 is 3114044322001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 610379687824 + 391854716289 = 781268^2 + 625983^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002234404113 - 25 = 1002234404081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1002234407113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501117202056 + 501117202057.

It is an arithmetic number, because the mean of its divisors is an integer number (501117202057).

Almost surely, 21002234404113 is an apocalyptic number.

It is an amenable number.

1002234404113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002234404113 is an equidigital number, since it uses as much as digits as its factorization.

1002234404113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1002234404113 its reverse (3114044322001), we get a palindrome (4116278726114).

The spelling of 1002234404113 in words is "one trillion, two billion, two hundred thirty-four million, four hundred four thousand, one hundred thirteen".