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100230002183557 is a prime number
BaseRepresentation
bin10110110010100010011101…
…101011010000110110000101
3111010212220011012000001102201
4112302202131223100312011
5101114132021024333212
6553101005523434501
730053243614351201
oct2662423553206605
9433786135001381
10100230002183557
1129a3333a2729a4
12b2a92b4b25a31
1343c085811304c
141aa722d749b01
15b8c32bb4eb57
hex5b289dad0d85

100230002183557 has 2 divisors, whose sum is σ = 100230002183558. Its totient is φ = 100230002183556.

The previous prime is 100230002183533. The next prime is 100230002183569. The reversal of 100230002183557 is 755381200032001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79719737245281 + 20510264938276 = 8928591^2 + 4528826^2 .

It is a cyclic number.

It is not a de Polignac number, because 100230002183557 - 219 = 100230001659269 is a prime.

It is a super-3 number, since 3×1002300021835573 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100230002183657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50115001091778 + 50115001091779.

It is an arithmetic number, because the mean of its divisors is an integer number (50115001091779).

Almost surely, 2100230002183557 is an apocalyptic number.

It is an amenable number.

100230002183557 is a deficient number, since it is larger than the sum of its proper divisors (1).

100230002183557 is an equidigital number, since it uses as much as digits as its factorization.

100230002183557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 37.

The spelling of 100230002183557 in words is "one hundred trillion, two hundred thirty billion, two million, one hundred eighty-three thousand, five hundred fifty-seven".