10023120011 has 2 divisors, whose sum is σ = 10023120012. Its totient is φ = 10023120010.

The previous prime is 10023119971. The next prime is 10023120013. The reversal of 10023120011 is 11002132001.

10023120011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10023120011 is a prime.

Together with 10023120013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10023119974 and 10023120001.

It is not a weakly prime, because it can be changed into another prime (10023120013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011560005 + 5011560006.

It is an arithmetic number, because the mean of its divisors is an integer number (5011560006).

Almost surely, 2^10023120011 is an apocalyptic number.

10023120011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10023120011 is an equidigital number, since it uses as much as digits as its factorization.

10023120011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10023120011 its reverse (11002132001), we get a palindrome (21025252012).

The spelling of 10023120011 in words is "ten billion, twenty-three million, one hundred twenty thousand, eleven".