Base | Representation |
---|---|
bin | 10010101010110110… |
… | …11110101010010111 |
3 | 221212112102101111122 |
4 | 21111123132222113 |
5 | 131011414421211 |
6 | 4334331554155 |
7 | 503245543415 |
oct | 112533365227 |
9 | 27775371448 |
10 | 10023201431 |
11 | 4283921651 |
12 | 1b388bb95b |
13 | c39751b29 |
14 | 6b12822b5 |
15 | 3d9e426db |
hex | 2556dea97 |
10023201431 has 2 divisors, whose sum is σ = 10023201432. Its totient is φ = 10023201430.
The previous prime is 10023201413. The next prime is 10023201439. The reversal of 10023201431 is 13410232001.
Together with previous prime (10023201413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (13410232001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10023201431 - 226 = 9956092567 is a prime.
It is a super-2 number, since 2×100232014312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10023201439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011600715 + 5011600716.
It is an arithmetic number, because the mean of its divisors is an integer number (5011600716).
Almost surely, 210023201431 is an apocalyptic number.
10023201431 is a deficient number, since it is larger than the sum of its proper divisors (1).
10023201431 is an equidigital number, since it uses as much as digits as its factorization.
10023201431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 10023201431 its reverse (13410232001), we get a palindrome (23433433432).
The spelling of 10023201431 in words is "ten billion, twenty-three million, two hundred one thousand, four hundred thirty-one".
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