Base | Representation |
---|---|
bin | 1001000111011011011100… |
… | …1001001001111100010001 |
3 | 1022111012201020002012102021 |
4 | 2101312313021021330101 |
5 | 2303210034210111423 |
6 | 33152335305051441 |
7 | 2053104005405446 |
oct | 221666711117421 |
9 | 38435636065367 |
10 | 10023231332113 |
11 | 321491286674a |
12 | 115a69ba86b81 |
13 | 57925712209c |
14 | 2691ac6379cd |
15 | 125ad96ea95d |
hex | 91db7249f11 |
10023231332113 has 2 divisors, whose sum is σ = 10023231332114. Its totient is φ = 10023231332112.
The previous prime is 10023231332087. The next prime is 10023231332117. The reversal of 10023231332113 is 31123313232001.
10023231332113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5316861212224 + 4706370119889 = 2305832^2 + 2169417^2 .
It is a cyclic number.
It is not a de Polignac number, because 10023231332113 - 217 = 10023231201041 is a prime.
It is not a weakly prime, because it can be changed into another prime (10023231332117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011615666056 + 5011615666057.
It is an arithmetic number, because the mean of its divisors is an integer number (5011615666057).
Almost surely, 210023231332113 is an apocalyptic number.
It is an amenable number.
10023231332113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10023231332113 is an equidigital number, since it uses as much as digits as its factorization.
10023231332113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 10023231332113 its reverse (31123313232001), we get a palindrome (41146544564114).
The spelling of 10023231332113 in words is "ten trillion, twenty-three billion, two hundred thirty-one million, three hundred thirty-two thousand, one hundred thirteen".
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