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10023450533441 is a prime number
BaseRepresentation
bin1001000111011100010000…
…1101010101111001000001
31022111020021111112210002222
42101313010031111321001
52303211011314032231
633152413135220425
72053112306524412
oct221670415257101
938436244483088
1010023450533441
113214a15573974
12115a741377715
13579290670107
142691cd7b7809
15125aeda9927b
hex91dc4355e41

10023450533441 has 2 divisors, whose sum is σ = 10023450533442. Its totient is φ = 10023450533440.

The previous prime is 10023450533431. The next prime is 10023450533443. The reversal of 10023450533441 is 14433505432001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7296589488400 + 2726861045041 = 2701220^2 + 1651321^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10023450533441 is a prime.

Together with 10023450533443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10023450533443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011725266720 + 5011725266721.

It is an arithmetic number, because the mean of its divisors is an integer number (5011725266721).

Almost surely, 210023450533441 is an apocalyptic number.

It is an amenable number.

10023450533441 is a deficient number, since it is larger than the sum of its proper divisors (1).

10023450533441 is an equidigital number, since it uses as much as digits as its factorization.

10023450533441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 10023450533441 its reverse (14433505432001), we get a palindrome (24456955965442).

The spelling of 10023450533441 in words is "ten trillion, twenty-three billion, four hundred fifty million, five hundred thirty-three thousand, four hundred forty-one".