Base | Representation |
---|---|
bin | 10010101010111101… |
… | …11101000100101111 |
3 | 221212121010200011101 |
4 | 21111132331010233 |
5 | 131012133044211 |
6 | 4334403303531 |
7 | 503256356404 |
oct | 112536750457 |
9 | 27777120141 |
10 | 10024112431 |
11 | 4284394043 |
12 | 1b3907aba7 |
13 | c399b0698 |
14 | 6b143c2ab |
15 | 3da0725c1 |
hex | 2557bd12f |
10024112431 has 2 divisors, whose sum is σ = 10024112432. Its totient is φ = 10024112430.
The previous prime is 10024112411. The next prime is 10024112443. The reversal of 10024112431 is 13421142001.
It is a strong prime.
It is an emirp because it is prime and its reverse (13421142001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10024112431 - 213 = 10024104239 is a prime.
It is a super-2 number, since 2×100241124312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10024112399 and 10024112408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10024112401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012056215 + 5012056216.
It is an arithmetic number, because the mean of its divisors is an integer number (5012056216).
Almost surely, 210024112431 is an apocalyptic number.
10024112431 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024112431 is an equidigital number, since it uses as much as digits as its factorization.
10024112431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10024112431 its reverse (13421142001), we get a palindrome (23445254432).
The spelling of 10024112431 in words is "ten billion, twenty-four million, one hundred twelve thousand, four hundred thirty-one".
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