Base | Representation |
---|---|
bin | 10010101011000000… |
… | …01011010111111011 |
3 | 221212121201222002202 |
4 | 21111200023113323 |
5 | 131012223330042 |
6 | 4334414220415 |
7 | 503262163421 |
oct | 112540132773 |
9 | 27777658082 |
10 | 10024433147 |
11 | 4284592aa3 |
12 | 1b391b470b |
13 | c39a93661 |
14 | 6b14c3111 |
15 | 3da0d7632 |
hex | 25580b5fb |
10024433147 has 2 divisors, whose sum is σ = 10024433148. Its totient is φ = 10024433146.
The previous prime is 10024433119. The next prime is 10024433191. The reversal of 10024433147 is 74133442001.
It is a weak prime.
It is an emirp because it is prime and its reverse (74133442001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10024433147 - 214 = 10024416763 is a prime.
It is not a weakly prime, because it can be changed into another prime (10024435147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012216573 + 5012216574.
It is an arithmetic number, because the mean of its divisors is an integer number (5012216574).
Almost surely, 210024433147 is an apocalyptic number.
10024433147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024433147 is an equidigital number, since it uses as much as digits as its factorization.
10024433147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 29.
Adding to 10024433147 its reverse (74133442001), we get a palindrome (84157875148).
The spelling of 10024433147 in words is "ten billion, twenty-four million, four hundred thirty-three thousand, one hundred forty-seven".
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