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10024433119 is a prime number
BaseRepresentation
bin10010101011000000…
…01011010111011111
3221212121201222001201
421111200023113133
5131012223324434
64334414220331
7503262163351
oct112540132737
927777658051
1010024433119
114284592a78
121b391b46a7
13c39a9363c
146b14c30d1
153da0d7614
hex25580b5df

10024433119 has 2 divisors, whose sum is σ = 10024433120. Its totient is φ = 10024433118.

The previous prime is 10024433101. The next prime is 10024433147. The reversal of 10024433119 is 91133442001.

It is an a-pointer prime, because the next prime (10024433147) can be obtained adding 10024433119 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10024433119 - 211 = 10024431071 is a prime.

It is a super-2 number, since 2×100244331192 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10024433819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012216559 + 5012216560.

It is an arithmetic number, because the mean of its divisors is an integer number (5012216560).

Almost surely, 210024433119 is an apocalyptic number.

10024433119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10024433119 is an equidigital number, since it uses as much as digits as its factorization.

10024433119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 10024433119 in words is "ten billion, twenty-four million, four hundred thirty-three thousand, one hundred nineteen".