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1002542113 is a prime number
BaseRepresentation
bin111011110000011…
…001010000100001
32120212110102020101
4323300121100201
54023122321423
6243251542401
733562316206
oct7360312041
92525412211
101002542113
114749aa801
1223b8baa01
1312c91a2b1
149720dcad
155d0347ad
hex3bc19421

1002542113 has 2 divisors, whose sum is σ = 1002542114. Its totient is φ = 1002542112.

The previous prime is 1002542111. The next prime is 1002542141. The reversal of 1002542113 is 3112452001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 819562384 + 182979729 = 28628^2 + 13527^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002542113 - 21 = 1002542111 is a prime.

Together with 1002542111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1002542111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501271056 + 501271057.

It is an arithmetic number, because the mean of its divisors is an integer number (501271057).

Almost surely, 21002542113 is an apocalyptic number.

It is an amenable number.

1002542113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002542113 is an equidigital number, since it uses as much as digits as its factorization.

1002542113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 1002542113 is about 31662.9454252127. The cubic root of 1002542113 is about 1000.8466539747.

Adding to 1002542113 its reverse (3112452001), we get a palindrome (4114994114).

The spelling of 1002542113 in words is "one billion, two million, five hundred forty-two thousand, one hundred thirteen".