Base | Representation |
---|---|
bin | 111011110000111… |
… | …110110111000101 |
3 | 2120212202020111211 |
4 | 323300332313011 |
5 | 4023142234013 |
6 | 243255131421 |
7 | 33563530225 |
oct | 7360766705 |
9 | 2525666454 |
10 | 1002696133 |
11 | 474aa549a |
12 | 23b973b71 |
13 | 12c97242a |
14 | 97250085 |
15 | 5d06523d |
hex | 3bc3edc5 |
1002696133 has 2 divisors, whose sum is σ = 1002696134. Its totient is φ = 1002696132.
The previous prime is 1002696113. The next prime is 1002696157. The reversal of 1002696133 is 3316962001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 596189889 + 406506244 = 24417^2 + 20162^2 .
It is a cyclic number.
It is not a de Polignac number, because 1002696133 - 29 = 1002695621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1002696095 and 1002696104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002696113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501348066 + 501348067.
It is an arithmetic number, because the mean of its divisors is an integer number (501348067).
Almost surely, 21002696133 is an apocalyptic number.
It is an amenable number.
1002696133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002696133 is an equidigital number, since it uses as much as digits as its factorization.
1002696133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 31.
The square root of 1002696133 is about 31665.3775123557. The cubic root of 1002696133 is about 1000.8979045262.
The spelling of 1002696133 in words is "one billion, two million, six hundred ninety-six thousand, one hundred thirty-three".
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