100300401211 has 2 divisors, whose sum is σ = 100300401212. Its totient is φ = 100300401210.

The previous prime is 100300401193. The next prime is 100300401241. The reversal of 100300401211 is 112104003001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100300401211 - 2⁷ = 100300401083 is a prime.

It is a super-3 number, since 3×100300401211³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100300401191 and 100300401200.

It is not a weakly prime, because it can be changed into another prime (100300401241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50150200605 + 50150200606.

It is an arithmetic number, because the mean of its divisors is an integer number (50150200606).

Almost surely, 2^100300401211 is an apocalyptic number.

100300401211 is a deficient number, since it is larger than the sum of its proper divisors (1).

100300401211 is an equidigital number, since it uses as much as digits as its factorization.

100300401211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100300401211 its reverse (112104003001), we get a palindrome (212404404212).

The spelling of 100300401211 in words is "one hundred billion, three hundred million, four hundred one thousand, two hundred eleven".