Base | Representation |
---|---|
bin | 10110110011101000010110… |
… | …100001100011001011110011 |
3 | 111011011001211222122121220011 |
4 | 112303220112201203023303 |
5 | 101121344212243440103 |
6 | 553155300124555351 |
7 | 30061541333335636 |
oct | 2663502641431363 |
9 | 434131758577804 |
10 | 100305044124403 |
11 | 29a62148508828 |
12 | b2bb9583b2b57 |
13 | 43c7956cb2341 |
14 | 1aaab0bc1dc1d |
15 | b8e26ebedd6d |
hex | 5b3a168632f3 |
100305044124403 has 2 divisors, whose sum is σ = 100305044124404. Its totient is φ = 100305044124402.
The previous prime is 100305044124401. The next prime is 100305044124511. The reversal of 100305044124403 is 304421440503001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100305044124403 - 21 = 100305044124401 is a prime.
It is a super-2 number, since 2×1003050441244032 (a number of 29 digits) contains 22 as substring.
Together with 100305044124401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (100305044124401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50152522062201 + 50152522062202.
It is an arithmetic number, because the mean of its divisors is an integer number (50152522062202).
Almost surely, 2100305044124403 is an apocalyptic number.
100305044124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
100305044124403 is an equidigital number, since it uses as much as digits as its factorization.
100305044124403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 100305044124403 its reverse (304421440503001), we get a palindrome (404726484627404).
The spelling of 100305044124403 in words is "one hundred trillion, three hundred five billion, forty-four million, one hundred twenty-four thousand, four hundred three".
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