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1003112021141 is a prime number
BaseRepresentation
bin11101001100011100010…
…00101011110010010101
310112220012121020110221022
432212032020223302111
5112413333134134031
62044453455530525
7132321023331656
oct16461610536225
93486177213838
101003112021141
1135746564849a
121424b0229a45
1373792c42379
143679d88d52d
151b15ea8697b
hexe98e22bc95

1003112021141 has 2 divisors, whose sum is σ = 1003112021142. Its totient is φ = 1003112021140.

The previous prime is 1003112021129. The next prime is 1003112021237. The reversal of 1003112021141 is 1411202113001.

1003112021141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 982717325041 + 20394696100 = 991321^2 + 142810^2 .

It is an emirp because it is prime and its reverse (1411202113001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1003112021141 - 238 = 728234114197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1003112021741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501556010570 + 501556010571.

It is an arithmetic number, because the mean of its divisors is an integer number (501556010571).

Almost surely, 21003112021141 is an apocalyptic number.

It is an amenable number.

1003112021141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003112021141 is an equidigital number, since it uses as much as digits as its factorization.

1003112021141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1003112021141 its reverse (1411202113001), we get a palindrome (2414314134142).

The spelling of 1003112021141 in words is "one trillion, three billion, one hundred twelve million, twenty-one thousand, one hundred forty-one".