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100314132415241 is a prime number
BaseRepresentation
bin10110110011110000110100…
…001110101000001100001001
3111011011221022100212122011112
4112303300310032220030021
5101122021320344241431
6553203402022340105
730062312500463453
oct2663606416501411
9434157270778145
10100314132415241
1129a65a91623198
12b301673b8a635
1343c8774b36624
141aab330c592d3
15b8e602a1ac2b
hex5b3c343a8309

100314132415241 has 2 divisors, whose sum is σ = 100314132415242. Its totient is φ = 100314132415240.

The previous prime is 100314132415207. The next prime is 100314132415267. The reversal of 100314132415241 is 142514231413001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88890408405241 + 11423724010000 = 9428171^2 + 3379900^2 .

It is a cyclic number.

It is not a de Polignac number, because 100314132415241 - 26 = 100314132415177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100314132415198 and 100314132415207.

It is not a weakly prime, because it can be changed into another prime (100314132415271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157066207620 + 50157066207621.

It is an arithmetic number, because the mean of its divisors is an integer number (50157066207621).

Almost surely, 2100314132415241 is an apocalyptic number.

It is an amenable number.

100314132415241 is a deficient number, since it is larger than the sum of its proper divisors (1).

100314132415241 is an equidigital number, since it uses as much as digits as its factorization.

100314132415241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 100314132415241 its reverse (142514231413001), we get a palindrome (242828363828242).

The spelling of 100314132415241 in words is "one hundred trillion, three hundred fourteen billion, one hundred thirty-two million, four hundred fifteen thousand, two hundred forty-one".