Base | Representation |
---|---|
bin | 10110110011110000110100… |
… | …001110101010001011101011 |
3 | 111011011221022100220001100211 |
4 | 112303300310032222023223 |
5 | 101122021320400022103 |
6 | 553203402022441551 |
7 | 30062312500526323 |
oct | 2663606416521353 |
9 | 434157270801324 |
10 | 100314132423403 |
11 | 29a65a91629338 |
12 | b301673b932b7 |
13 | 43c8774b3a262 |
14 | 1aab330c5c283 |
15 | b8e602a1d36d |
hex | 5b3c343aa2eb |
100314132423403 has 2 divisors, whose sum is σ = 100314132423404. Its totient is φ = 100314132423402.
The previous prime is 100314132423389. The next prime is 100314132423433. The reversal of 100314132423403 is 304324231413001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100314132423403 - 241 = 98115109167851 is a prime.
It is not a weakly prime, because it can be changed into another prime (100314132423433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157066211701 + 50157066211702.
It is an arithmetic number, because the mean of its divisors is an integer number (50157066211702).
Almost surely, 2100314132423403 is an apocalyptic number.
100314132423403 is a deficient number, since it is larger than the sum of its proper divisors (1).
100314132423403 is an equidigital number, since it uses as much as digits as its factorization.
100314132423403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 100314132423403 its reverse (304324231413001), we get a palindrome (404638363836404).
The spelling of 100314132423403 in words is "one hundred trillion, three hundred fourteen billion, one hundred thirty-two million, four hundred twenty-three thousand, four hundred three".
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