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100314132423433 is a prime number
BaseRepresentation
bin10110110011110000110100…
…001110101010001100001001
3111011011221022100220001101221
4112303300310032222030021
5101122021320400022213
6553203402022442041
730062312500526365
oct2663606416521411
9434157270801357
10100314132423433
1129a65a91629365
12b301673b93321
1343c8774b3a286
141aab330c5c2a5
15b8e602a1d38d
hex5b3c343aa309

100314132423433 has 2 divisors, whose sum is σ = 100314132423434. Its totient is φ = 100314132423432.

The previous prime is 100314132423403. The next prime is 100314132423473. The reversal of 100314132423433 is 334324231413001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72527655244489 + 27786477178944 = 8516317^2 + 5271288^2 .

It is an emirp because it is prime and its reverse (334324231413001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100314132423433 - 213 = 100314132415241 is a prime.

It is not a weakly prime, because it can be changed into another prime (100314132423403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157066211716 + 50157066211717.

It is an arithmetic number, because the mean of its divisors is an integer number (50157066211717).

Almost surely, 2100314132423433 is an apocalyptic number.

It is an amenable number.

100314132423433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100314132423433 is an equidigital number, since it uses as much as digits as its factorization.

100314132423433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 100314132423433 its reverse (334324231413001), we get a palindrome (434638363836434).

The spelling of 100314132423433 in words is "one hundred trillion, three hundred fourteen billion, one hundred thirty-two million, four hundred twenty-three thousand, four hundred thirty-three".