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1003153200145 = 51991008194171
BaseRepresentation
bin11101001100100001001…
…01110001010000010001
310112220022110201120220121
432212100211301100101
5112413424204401040
62044501530310241
7132322033340245
oct16462045612021
93486273646817
101003153200145
11357486913928
12142501b88381
137379b62c745
14367a512c425
151b1634bcc4a
hexe990971411

1003153200145 has 8 divisors (see below), whose sum is σ = 1209833006400. Its totient is φ = 798489782640.

The previous prime is 1003153200139. The next prime is 1003153200187. The reversal of 1003153200145 is 5410023513001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1003153200145 - 219 = 1003152675857 is a prime.

It is a super-2 number, since 2×10031532001452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 504096091 + ... + 504098080.

It is an arithmetic number, because the mean of its divisors is an integer number (151229125800).

Almost surely, 21003153200145 is an apocalyptic number.

It is an amenable number.

1003153200145 is a deficient number, since it is larger than the sum of its proper divisors (206679806255).

1003153200145 is a wasteful number, since it uses less digits than its factorization.

1003153200145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008194375.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 1003153200145 its reverse (5410023513001), we get a palindrome (6413176713146).

The spelling of 1003153200145 in words is "one trillion, three billion, one hundred fifty-three million, two hundred thousand, one hundred forty-five".

Divisors: 1 5 199 995 1008194171 5040970855 200630640029 1003153200145