Base | Representation |
---|---|
bin | 10010101011111010… |
… | …00101111101010101 |
3 | 221220011000001220021 |
4 | 21111331011331111 |
5 | 131021143410031 |
6 | 4335244505141 |
7 | 503413463503 |
oct | 112575057525 |
9 | 27804001807 |
10 | 10032013141 |
11 | 428889aa57 |
12 | 1b3b84b1b1 |
13 | c3b518867 |
14 | 6b24d7673 |
15 | 3daad3511 |
hex | 255f45f55 |
10032013141 has 2 divisors, whose sum is σ = 10032013142. Its totient is φ = 10032013140.
The previous prime is 10032013099. The next prime is 10032013169. The reversal of 10032013141 is 14131023001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8272630116 + 1759383025 = 90954^2 + 41945^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10032013141 is a prime.
It is a super-2 number, since 2×100320131412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10032013171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016006570 + 5016006571.
It is an arithmetic number, because the mean of its divisors is an integer number (5016006571).
Almost surely, 210032013141 is an apocalyptic number.
It is an amenable number.
10032013141 is a deficient number, since it is larger than the sum of its proper divisors (1).
10032013141 is an equidigital number, since it uses as much as digits as its factorization.
10032013141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 10032013141 its reverse (14131023001), we get a palindrome (24163036142).
The spelling of 10032013141 in words is "ten billion, thirty-two million, thirteen thousand, one hundred forty-one".
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