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10032013141 is a prime number
BaseRepresentation
bin10010101011111010…
…00101111101010101
3221220011000001220021
421111331011331111
5131021143410031
64335244505141
7503413463503
oct112575057525
927804001807
1010032013141
11428889aa57
121b3b84b1b1
13c3b518867
146b24d7673
153daad3511
hex255f45f55

10032013141 has 2 divisors, whose sum is σ = 10032013142. Its totient is φ = 10032013140.

The previous prime is 10032013099. The next prime is 10032013169. The reversal of 10032013141 is 14131023001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8272630116 + 1759383025 = 90954^2 + 41945^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10032013141 is a prime.

It is a super-2 number, since 2×100320131412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10032013171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016006570 + 5016006571.

It is an arithmetic number, because the mean of its divisors is an integer number (5016006571).

Almost surely, 210032013141 is an apocalyptic number.

It is an amenable number.

10032013141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10032013141 is an equidigital number, since it uses as much as digits as its factorization.

10032013141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10032013141 its reverse (14131023001), we get a palindrome (24163036142).

The spelling of 10032013141 in words is "ten billion, thirty-two million, thirteen thousand, one hundred forty-one".