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10032999967 is a prime number
BaseRepresentation
bin10010101100000001…
…10110111000011111
3221220012212012120101
421112000312320133
5131021421444332
64335322001531
7503425043524
oct112600667037
927805765511
1010032999967
114289404411
121b400462a7
13c3b7a2a93
146b26b314b
153dac2aae7
hex256036e1f

10032999967 has 2 divisors, whose sum is σ = 10032999968. Its totient is φ = 10032999966.

The previous prime is 10032999943. The next prime is 10032999971. The reversal of 10032999967 is 76999923001.

10032999967 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (76999923001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10032999967 is a prime.

It is a super-3 number, since 3×100329999673 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10032999937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016499983 + 5016499984.

It is an arithmetic number, because the mean of its divisors is an integer number (5016499984).

Almost surely, 210032999967 is an apocalyptic number.

10032999967 is a deficient number, since it is larger than the sum of its proper divisors (1).

10032999967 is an equidigital number, since it uses as much as digits as its factorization.

10032999967 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1653372, while the sum is 55.

The spelling of 10032999967 in words is "ten billion, thirty-two million, nine hundred ninety-nine thousand, nine hundred sixty-seven".