Base | Representation |
---|---|
bin | 1001000111111111111101… |
… | …0001011011011011011111 |
3 | 1022112011000012121222102211 |
4 | 2101333333101123123133 |
5 | 2303340122014120124 |
6 | 33201035550301251 |
7 | 2053601604514462 |
oct | 221777721333337 |
9 | 38464005558384 |
10 | 10033031395039 |
11 | 3218a91731004 |
12 | 1160575ab7827 |
13 | 57a159577aa3 |
14 | 26985bdd32d9 |
15 | 125eaec62e94 |
hex | 91fff45b6df |
10033031395039 has 2 divisors, whose sum is σ = 10033031395040. Its totient is φ = 10033031395038.
The previous prime is 10033031395027. The next prime is 10033031395067. The reversal of 10033031395039 is 93059313033001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10033031395039 - 25 = 10033031395007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10033031394992 and 10033031395010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10033031395339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5016515697519 + 5016515697520.
It is an arithmetic number, because the mean of its divisors is an integer number (5016515697520).
Almost surely, 210033031395039 is an apocalyptic number.
10033031395039 is a deficient number, since it is larger than the sum of its proper divisors (1).
10033031395039 is an equidigital number, since it uses as much as digits as its factorization.
10033031395039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98415, while the sum is 40.
The spelling of 10033031395039 in words is "ten trillion, thirty-three billion, thirty-one million, three hundred ninety-five thousand, thirty-nine".
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