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100331311012157 is a prime number
BaseRepresentation
bin10110110100000000110100…
…001001110001100100111101
3111011020120122120102202222202
4112310000310021301210331
5101122312011104342112
6553215322403321245
730063461263240421
oct2664006411614475
9434216576382882
10100331311012157
1129a722a7486325
12b304a69080225
1343ca281b2c084
141aac0c0548b81
15b8ecaac206c2
hex5b403427193d

100331311012157 has 2 divisors, whose sum is σ = 100331311012158. Its totient is φ = 100331311012156.

The previous prime is 100331311012147. The next prime is 100331311012277. The reversal of 100331311012157 is 751210113133001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74095494799876 + 26235816212281 = 8607874^2 + 5122091^2 .

It is an emirp because it is prime and its reverse (751210113133001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100331311012157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100331311012147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50165655506078 + 50165655506079.

It is an arithmetic number, because the mean of its divisors is an integer number (50165655506079).

Almost surely, 2100331311012157 is an apocalyptic number.

It is an amenable number.

100331311012157 is a deficient number, since it is larger than the sum of its proper divisors (1).

100331311012157 is an equidigital number, since it uses as much as digits as its factorization.

100331311012157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1890, while the sum is 29.

Adding to 100331311012157 its reverse (751210113133001), we get a palindrome (851541424145158).

The spelling of 100331311012157 in words is "one hundred trillion, three hundred thirty-one billion, three hundred eleven million, twelve thousand, one hundred fifty-seven".