1003423140331 has 2 divisors, whose sum is σ = 1003423140332. Its totient is φ = 1003423140330.

The previous prime is 1003423140283. The next prime is 1003423140373. The reversal of 1003423140331 is 1330413243001.

1003423140331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1003423140331 - 2¹³ = 1003423132139 is a prime.

It is a super-2 number, since 2×1003423140331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1003423140296 and 1003423140305.

It is not a weakly prime, because it can be changed into another prime (1003423140631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501711570165 + 501711570166.

It is an arithmetic number, because the mean of its divisors is an integer number (501711570166).

Almost surely, 2^{1003423140331} is an apocalyptic number.

1003423140331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003423140331 is an equidigital number, since it uses as much as digits as its factorization.

1003423140331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1003423140331 its reverse (1330413243001), we get a palindrome (2333836383332).

The spelling of 1003423140331 in words is "one trillion, three billion, four hundred twenty-three million, one hundred forty thousand, three hundred thirty-one".