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10034250053 is a prime number
BaseRepresentation
bin10010101100001011…
…01000000101000101
3221220022012201100212
421112011220011011
5131022232000203
64335404445205
7503441501222
oct112605500505
927808181325
1010034250053
11428a088643
121b40549805
13c3bb1ca89
146b291a949
153dadc61d8
hex256168145

10034250053 has 2 divisors, whose sum is σ = 10034250054. Its totient is φ = 10034250052.

The previous prime is 10034250047. The next prime is 10034250071. The reversal of 10034250053 is 35005243001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8533694884 + 1500555169 = 92378^2 + 38737^2 .

It is a cyclic number.

It is not a de Polignac number, because 10034250053 - 224 = 10017472837 is a prime.

It is a super-2 number, since 2×100342500532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10034250013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017125026 + 5017125027.

It is an arithmetic number, because the mean of its divisors is an integer number (5017125027).

Almost surely, 210034250053 is an apocalyptic number.

It is an amenable number.

10034250053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10034250053 is an equidigital number, since it uses as much as digits as its factorization.

10034250053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 23.

Adding to 10034250053 its reverse (35005243001), we get a palindrome (45039493054).

The spelling of 10034250053 in words is "ten billion, thirty-four million, two hundred fifty thousand, fifty-three".