Base | Representation |
---|---|
bin | 10010101100001011… |
… | …01000000101000101 |
3 | 221220022012201100212 |
4 | 21112011220011011 |
5 | 131022232000203 |
6 | 4335404445205 |
7 | 503441501222 |
oct | 112605500505 |
9 | 27808181325 |
10 | 10034250053 |
11 | 428a088643 |
12 | 1b40549805 |
13 | c3bb1ca89 |
14 | 6b291a949 |
15 | 3dadc61d8 |
hex | 256168145 |
10034250053 has 2 divisors, whose sum is σ = 10034250054. Its totient is φ = 10034250052.
The previous prime is 10034250047. The next prime is 10034250071. The reversal of 10034250053 is 35005243001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8533694884 + 1500555169 = 92378^2 + 38737^2 .
It is a cyclic number.
It is not a de Polignac number, because 10034250053 - 224 = 10017472837 is a prime.
It is a super-2 number, since 2×100342500532 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10034250013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017125026 + 5017125027.
It is an arithmetic number, because the mean of its divisors is an integer number (5017125027).
Almost surely, 210034250053 is an apocalyptic number.
It is an amenable number.
10034250053 is a deficient number, since it is larger than the sum of its proper divisors (1).
10034250053 is an equidigital number, since it uses as much as digits as its factorization.
10034250053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 23.
Adding to 10034250053 its reverse (35005243001), we get a palindrome (45039493054).
The spelling of 10034250053 in words is "ten billion, thirty-four million, two hundred fifty thousand, fifty-three".
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