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10034334091 is a prime number
BaseRepresentation
bin10010101100001011…
…11100100110001011
3221220022100222122101
421112011330212023
5131022242142331
64335410334231
7503442301225
oct112605744613
927808328571
1010034334091
11428a1357a1
121b4058a377
13c3bb4c0c2
146b293d415
153dade1061
hex25617c98b

10034334091 has 2 divisors, whose sum is σ = 10034334092. Its totient is φ = 10034334090.

The previous prime is 10034334059. The next prime is 10034334119. The reversal of 10034334091 is 19043343001.

10034334091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (10034334119) can be obtained adding 10034334091 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10034334091 - 25 = 10034334059 is a prime.

It is not a weakly prime, because it can be changed into another prime (10034334041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017167045 + 5017167046.

It is an arithmetic number, because the mean of its divisors is an integer number (5017167046).

Almost surely, 210034334091 is an apocalyptic number.

10034334091 is a deficient number, since it is larger than the sum of its proper divisors (1).

10034334091 is an equidigital number, since it uses as much as digits as its factorization.

10034334091 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 10034334091 its reverse (19043343001), we get a palindrome (29077677092).

The spelling of 10034334091 in words is "ten billion, thirty-four million, three hundred thirty-four thousand, ninety-one".