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1003554234142 = 2501777117071
BaseRepresentation
bin11101001101010000111…
…11100101111100011110
310112221100102100020010121
432212220133211330132
5112420234340443032
62045005414025154
7132335003146465
oct16465037457436
93487312306117
101003554234142
11357672225689
121425b43481ba
1373833743875
14368024c19dc
151b1887d7a97
hexe9a87e5f1e

1003554234142 has 4 divisors (see below), whose sum is σ = 1505331351216. Its totient is φ = 501777117070.

The previous prime is 1003554234139. The next prime is 1003554234211. The reversal of 1003554234142 is 2414324553001.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×10035542341422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1003554234098 and 1003554234107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250888558534 + ... + 250888558537.

It is an arithmetic number, because the mean of its divisors is an integer number (376332837804).

Almost surely, 21003554234142 is an apocalyptic number.

1003554234142 is a deficient number, since it is larger than the sum of its proper divisors (501777117074).

1003554234142 is an equidigital number, since it uses as much as digits as its factorization.

1003554234142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 501777117073.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 1003554234142 its reverse (2414324553001), we get a palindrome (3417878787143).

The spelling of 1003554234142 in words is "one trillion, three billion, five hundred fifty-four million, two hundred thirty-four thousand, one hundred forty-two".

Divisors: 1 2 501777117071 1003554234142