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1004005235147 is a prime number
BaseRepresentation
bin11101001110000110110…
…00000001100111001011
310112222111211222110012112
432213003120001213023
5112422200320011042
62045122244332535
7132352120455305
oct16470330014713
93488454873175
101004005235147
11357883865392
121426bb3a414b
13738a6001075
1436846360975
151b1b31c2982
hexe9c36019cb

1004005235147 has 2 divisors, whose sum is σ = 1004005235148. Its totient is φ = 1004005235146.

The previous prime is 1004005235131. The next prime is 1004005235209. The reversal of 1004005235147 is 7415325004001.

It is a weak prime.

It is an emirp because it is prime and its reverse (7415325004001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1004005235147 - 24 = 1004005235131 is a prime.

It is a super-2 number, since 2×10040052351472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1004005235747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502002617573 + 502002617574.

It is an arithmetic number, because the mean of its divisors is an integer number (502002617574).

Almost surely, 21004005235147 is an apocalyptic number.

1004005235147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004005235147 is an equidigital number, since it uses as much as digits as its factorization.

1004005235147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 32.

The spelling of 1004005235147 in words is "one trillion, four billion, five million, two hundred thirty-five thousand, one hundred forty-seven".