Base | Representation |
---|---|
bin | 1001001000011010010111… |
… | …0011111101101001011111 |
3 | 1022112211022020220102200111 |
4 | 2102012211303331221133 |
5 | 2303444131312330442 |
6 | 33204211225110451 |
7 | 2054242354402402 |
oct | 222064563755137 |
9 | 38484266812614 |
10 | 10040120433247 |
11 | 3220a9a26a373 |
12 | 1161a14028427 |
13 | 57aa19156c58 |
14 | 269d316c9d39 |
15 | 1262772b8b17 |
hex | 921a5cfda5f |
10040120433247 has 2 divisors, whose sum is σ = 10040120433248. Its totient is φ = 10040120433246.
The previous prime is 10040120433229. The next prime is 10040120433269. The reversal of 10040120433247 is 74233402104001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10040120433247 - 211 = 10040120431199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10040120433547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020060216623 + 5020060216624.
It is an arithmetic number, because the mean of its divisors is an integer number (5020060216624).
Almost surely, 210040120433247 is an apocalyptic number.
10040120433247 is a deficient number, since it is larger than the sum of its proper divisors (1).
10040120433247 is an equidigital number, since it uses as much as digits as its factorization.
10040120433247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 10040120433247 its reverse (74233402104001), we get a palindrome (84273522537248).
The spelling of 10040120433247 in words is "ten trillion, forty billion, one hundred twenty million, four hundred thirty-three thousand, two hundred forty-seven".
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