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100401439981 is a prime number
BaseRepresentation
bin101110110000001100…
…1000110010011101101
3100121011011000121101011
41131200121012103231
53121110232034411
6114042423145221
710153020105313
oct1354031062355
9317134017334
10100401439981
1139641aa4987
12175602a5211
139610a365ab
144c064bc0b3
1529295d4c21
hex17606464ed

100401439981 has 2 divisors, whose sum is σ = 100401439982. Its totient is φ = 100401439980.

The previous prime is 100401439889. The next prime is 100401440039. The reversal of 100401439981 is 189934104001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70813999881 + 29587440100 = 266109^2 + 172010^2 .

It is a cyclic number.

It is not a de Polignac number, because 100401439981 - 233 = 91811505389 is a prime.

It is a super-2 number, since 2×1004014399812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100401434981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200719990 + 50200719991.

It is an arithmetic number, because the mean of its divisors is an integer number (50200719991).

Almost surely, 2100401439981 is an apocalyptic number.

It is an amenable number.

100401439981 is a deficient number, since it is larger than the sum of its proper divisors (1).

100401439981 is an equidigital number, since it uses as much as digits as its factorization.

100401439981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 40.

The spelling of 100401439981 in words is "one hundred billion, four hundred one million, four hundred thirty-nine thousand, nine hundred eighty-one".