Base | Representation |
---|---|
bin | 10010101100111000… |
… | …01001100110000111 |
3 | 221220201022200202012 |
4 | 21112130021212013 |
5 | 131030234421003 |
6 | 4340135204435 |
7 | 503542622321 |
oct | 112634114607 |
9 | 27821280665 |
10 | 10040154503 |
11 | 4292450755 |
12 | 1b4251671b |
13 | c40109432 |
14 | 6b3616611 |
15 | 3db6908d8 |
hex | 256709987 |
10040154503 has 2 divisors, whose sum is σ = 10040154504. Its totient is φ = 10040154502.
The previous prime is 10040154461. The next prime is 10040154541. The reversal of 10040154503 is 30545104001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10040154503 - 216 = 10040088967 is a prime.
It is a super-2 number, since 2×100401545032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10040154403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020077251 + 5020077252.
It is an arithmetic number, because the mean of its divisors is an integer number (5020077252).
Almost surely, 210040154503 is an apocalyptic number.
10040154503 is a deficient number, since it is larger than the sum of its proper divisors (1).
10040154503 is an equidigital number, since it uses as much as digits as its factorization.
10040154503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 10040154503 its reverse (30545104001), we get a palindrome (40585258504).
The spelling of 10040154503 in words is "ten billion, forty million, one hundred fifty-four thousand, five hundred three".
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