Base | Representation |
---|---|
bin | 101110110000001110… |
… | …1011000000101000111 |
3 | 100121011020010120121101 |
4 | 1131200131120011013 |
5 | 3121111023430401 |
6 | 114042503200531 |
7 | 10153032455521 |
oct | 1354035300507 |
9 | 317136116541 |
10 | 100402561351 |
11 | 396426a0434 |
12 | 17560746147 |
13 | 9611039b21 |
14 | 4c066d0a11 |
15 | 2929757101 |
hex | 1760758147 |
100402561351 has 2 divisors, whose sum is σ = 100402561352. Its totient is φ = 100402561350.
The previous prime is 100402561339. The next prime is 100402561367. The reversal of 100402561351 is 153165204001.
It is a weak prime.
It is an emirp because it is prime and its reverse (153165204001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100402561351 - 211 = 100402559303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100402567351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50201280675 + 50201280676.
It is an arithmetic number, because the mean of its divisors is an integer number (50201280676).
Almost surely, 2100402561351 is an apocalyptic number.
100402561351 is a deficient number, since it is larger than the sum of its proper divisors (1).
100402561351 is an equidigital number, since it uses as much as digits as its factorization.
100402561351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 100402561351 its reverse (153165204001), we get a palindrome (253567765352).
The spelling of 100402561351 in words is "one hundred billion, four hundred two million, five hundred sixty-one thousand, three hundred fifty-one".
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