Base | Representation |
---|---|
bin | 101110110000010001… |
… | …1101111110100001001 |
3 | 100121011100021102112021 |
4 | 1131200203233310021 |
5 | 3121111440401213 |
6 | 114043003044441 |
7 | 10153052612542 |
oct | 1354043576411 |
9 | 317140242467 |
10 | 100404231433 |
11 | 39643631170 |
12 | 17561210721 |
13 | 96114a303c |
14 | 4c06a074c9 |
15 | 2929986d8d |
hex | 17608efd09 |
100404231433 has 32 divisors (see below), whose sum is σ = 115550582400. Its totient is φ = 86388556800.
The previous prime is 100404231407. The next prime is 100404231443. The reversal of 100404231433 is 334132404001.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100404231433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100404231398 and 100404231407.
It is not an unprimeable number, because it can be changed into a prime (100404231443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26694273 + ... + 26698033.
It is an arithmetic number, because the mean of its divisors is an integer number (3610955700).
Almost surely, 2100404231433 is an apocalyptic number.
It is an amenable number.
100404231433 is a deficient number, since it is larger than the sum of its proper divisors (15146350967).
100404231433 is a wasteful number, since it uses less digits than its factorization.
100404231433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5433.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 100404231433 its reverse (334132404001), we get a palindrome (434536635434).
The spelling of 100404231433 in words is "one hundred billion, four hundred four million, two hundred thirty-one thousand, four hundred thirty-three".
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