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10040440231 is a prime number
BaseRepresentation
bin10010101100111010…
…01111010110100111
3221220201212012200201
421112131033112213
5131030323041411
64340145251331
7503545222333
oct112635172647
927821765621
1010040440231
114292626398
121b42633b47
13c401a94c3
146b368c7c3
153db6ea3c1
hex25674f5a7

10040440231 has 2 divisors, whose sum is σ = 10040440232. Its totient is φ = 10040440230.

The previous prime is 10040440181. The next prime is 10040440247. The reversal of 10040440231 is 13204404001.

It is a strong prime.

It is an emirp because it is prime and its reverse (13204404001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10040440231 is a prime.

It is a super-2 number, since 2×100404402312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10040440199 and 10040440208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10040440831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020220115 + 5020220116.

It is an arithmetic number, because the mean of its divisors is an integer number (5020220116).

Almost surely, 210040440231 is an apocalyptic number.

10040440231 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040440231 is an equidigital number, since it uses as much as digits as its factorization.

10040440231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 10040440231 its reverse (13204404001), we get a palindrome (23244844232).

The spelling of 10040440231 in words is "ten billion, forty million, four hundred forty thousand, two hundred thirty-one".