10040984281981 has 2 divisors, whose sum is σ = 10040984281982. Its totient is φ = 10040984281980.

The previous prime is 10040984281969. The next prime is 10040984282041. The reversal of 10040984281981 is 18918248904001.

10040984281981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9704682874756 + 336301407225 = 3115234^2 + 579915^2 .

It is a cyclic number.

It is not a de Polignac number, because 10040984281981 - 2⁹ = 10040984281469 is a prime.

It is a super-2 number, since 2×10040984281981² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10040984281481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020492140990 + 5020492140991.

It is an arithmetic number, because the mean of its divisors is an integer number (5020492140991).

Almost surely, 2^{10040984281981} is an apocalyptic number.

It is an amenable number.

10040984281981 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040984281981 is an equidigital number, since it uses as much as digits as its factorization.

10040984281981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1327104, while the sum is 55.

The spelling of 10040984281981 in words is "ten trillion, forty billion, nine hundred eighty-four million, two hundred eighty-one thousand, nine hundred eighty-one".