Base | Representation |
---|---|
bin | 10010101101000000… |
… | …01000110101101101 |
3 | 221220210021210212121 |
4 | 21112200020311231 |
5 | 131031021344411 |
6 | 4340213432541 |
7 | 503554535341 |
oct | 112640106555 |
9 | 27823253777 |
10 | 10041199981 |
11 | 4292aa518a |
12 | 1b4293b751 |
13 | c403b4267 |
14 | 6b3809621 |
15 | 3db7ea571 |
hex | 256808d6d |
10041199981 has 2 divisors, whose sum is σ = 10041199982. Its totient is φ = 10041199980.
The previous prime is 10041199939. The next prime is 10041200017. The reversal of 10041199981 is 18999114001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6587757225 + 3453442756 = 81165^2 + 58766^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10041199981 is a prime.
It is a super-2 number, since 2×100411999812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10041199381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020599990 + 5020599991.
It is an arithmetic number, because the mean of its divisors is an integer number (5020599991).
Almost surely, 210041199981 is an apocalyptic number.
It is an amenable number.
10041199981 is a deficient number, since it is larger than the sum of its proper divisors (1).
10041199981 is an equidigital number, since it uses as much as digits as its factorization.
10041199981 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 43.
The spelling of 10041199981 in words is "ten billion, forty-one million, one hundred ninety-nine thousand, nine hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •