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10041201340433 is a prime number
BaseRepresentation
bin1001001000011110011000…
…1111010011000000010001
31022112221002120211012120222
42102013212033103000101
52304003340020343213
633204510400442425
72054311221065324
oct222074617230021
938487076735528
1010041201340433
1132214a442399a
121162076019415
1357ab5c0813c3
14269dd50987bb
151262dc12c808
hex921e63d3011

10041201340433 has 2 divisors, whose sum is σ = 10041201340434. Its totient is φ = 10041201340432.

The previous prime is 10041201340381. The next prime is 10041201340439. The reversal of 10041201340433 is 33404310214001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8861475173329 + 1179726167104 = 2976823^2 + 1086152^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10041201340433 is a prime.

It is a super-2 number, since 2×100412013404332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10041201340439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020600670216 + 5020600670217.

It is an arithmetic number, because the mean of its divisors is an integer number (5020600670217).

Almost surely, 210041201340433 is an apocalyptic number.

It is an amenable number.

10041201340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041201340433 is an equidigital number, since it uses as much as digits as its factorization.

10041201340433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 10041201340433 its reverse (33404310214001), we get a palindrome (43445511554434).

The spelling of 10041201340433 in words is "ten trillion, forty-one billion, two hundred one million, three hundred forty thousand, four hundred thirty-three".