Base | Representation |
---|---|
bin | 10010101101000000… |
… | …01011111110000011 |
3 | 221220210022110110111 |
4 | 21112200023332003 |
5 | 131031022302203 |
6 | 4340214012151 |
7 | 503554620616 |
oct | 112640137603 |
9 | 27823273414 |
10 | 10041212803 |
11 | 4293003886 |
12 | 1b42947057 |
13 | c403ba04b |
14 | 6b381017d |
15 | 3db7ee26d |
hex | 25680bf83 |
10041212803 has 2 divisors, whose sum is σ = 10041212804. Its totient is φ = 10041212802.
The previous prime is 10041212791. The next prime is 10041212837. The reversal of 10041212803 is 30821214001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10041212803 - 25 = 10041212771 is a prime.
It is a super-2 number, since 2×100412128032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10041212873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020606401 + 5020606402.
It is an arithmetic number, because the mean of its divisors is an integer number (5020606402).
Almost surely, 210041212803 is an apocalyptic number.
10041212803 is a deficient number, since it is larger than the sum of its proper divisors (1).
10041212803 is an equidigital number, since it uses as much as digits as its factorization.
10041212803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 10041212803 its reverse (30821214001), we get a palindrome (40862426804).
The spelling of 10041212803 in words is "ten billion, forty-one million, two hundred twelve thousand, eight hundred three".
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