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100412140111 = 472136428513
BaseRepresentation
bin101110110000100000…
…1111010101001001111
3100121011220011020012021
41131201001322221033
53121121001440421
6114043444351011
710153210052113
oct1354101725117
9317156136167
10100412140111
1139648043068
12175639a5467
139613011a2a
144c07aa5743
15292a4ea341
hex176107aa4f

100412140111 has 4 divisors (see below), whose sum is σ = 102548568672. Its totient is φ = 98275711552.

The previous prime is 100412140099. The next prime is 100412140121. The reversal of 100412140111 is 111041214001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100412140111 - 211 = 100412138063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100412140121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1068214210 + ... + 1068214303.

It is an arithmetic number, because the mean of its divisors is an integer number (25637142168).

Almost surely, 2100412140111 is an apocalyptic number.

100412140111 is a deficient number, since it is larger than the sum of its proper divisors (2136428561).

100412140111 is an equidigital number, since it uses as much as digits as its factorization.

100412140111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2136428560.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 100412140111 its reverse (111041214001), we get a palindrome (211453354112).

The spelling of 100412140111 in words is "one hundred billion, four hundred twelve million, one hundred forty thousand, one hundred eleven".

Divisors: 1 47 2136428513 100412140111